CameraIcon

SearchIcon

MyQuestionIcon

233

You visited us 233 times! Enjoying our articles? Unlock Full Access!

Self Induction

A coil of 100...

Question

A coil of 100 turns carries a current of 5mA and creates a magnetic flux of $10^{- 5}$ Weber. The inductance is

A

0.2H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

2mH

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

2H

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

0.2mH

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 2H
Use the relation

$n ϕ = L i$
$100 \times 10^{- 5} = L \times 5 \times 10^{- 3}$
$L = 2 H$

Suggest Corrections

thumbs-up

0

Similar questions

Q. A coil of 100 turns carries a current of 5mA and creates a magnetic flux of

10^{- 5}

Weber. The inductance is

Q. A coil of N=100 turns carries a current I=5 A and creates a magnetic flux

φ = 10^{- 5} T m^{- 2}

per turn. The value of its inductance L will be

Q. What will be the self inductance of a coil of 100 turns if a current of 5 A produces a magnetic flux

5 \times 10^{- 5}

Q. A coil having 100 turns is carrying of 2 A. If magnetic flux linked with each turn of coil is

5 \times 10^{3}

Wb then the self inductance of the coil is:

Q. A magnetic flux of 8 × 10⁻⁴ weber is linked with each turn of a 200-turn coil when there is an electric current of 4 A in it. Calculate the self-inductance of the coil.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Self and Mutual Inductance

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard XIII Physics

Join BYJU'S Learning Program

CrossIcon