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Standard XII

Physics

Magnetic Flux and Faraday's Law

A coil of are...

Question

A coil of area $10 {c m}^{2}$ and $10$ turns is in magnetic field directed perpendicular to the plane and changing at a rate of $10^{8}$ $g a u s s / s$ . The resistance of coil is $20 Ω$ . The current in the coil will be

0.5 A

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5 \times 10^{- 3} A

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0.05 A

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5 A

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Solution

The correct option is D $5 A$
$i = \frac{e}{R}$
$= \frac{N (Δ ϕ / Δ t)}{R} = \frac{N S (Δ B / Δ t)}{R}$
$= \frac{10 (10 \times 10^{- 4}) (10^{4})}{20} = 5 A$

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A coil of area 10cm2 and 10 turns is in magnetic field directed perpendicular to the plane and changing at a rate of 108 gauss/s. The resistance of coil is 20Ω. The current in the coil will be

The correct option is D 5Ai=eR=N(Δϕ/Δt)R=NS(ΔB/Δt)R=10(10×10−4)(104)20=5A

A coil of area $10 {c m}^{2}$ and $10$ turns is in magnetic field directed perpendicular to the plane and changing at a rate of $10^{8}$ $g a u s s / s$ . The resistance of coil is $20 Ω$ . The current in the coil will be

The correct option is D $5 A$
$i = \frac{e}{R}$
$= \frac{N (Δ ϕ / Δ t)}{R} = \frac{N S (Δ B / Δ t)}{R}$
$= \frac{10 (10 \times 10^{- 4}) (10^{4})}{20} = 5 A$