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Question

A coil of area 100 cm^2 having 500 turns carries a current of 1 m A. It is suspended in a uniform magnetic field of induction 10^-3wb/m^2. Its plane making an angle of 60° with the lines of induction. the torque acting on the coil is

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Solution

T=BAIN cos theeta
B =10^-3
A=100cm2=100*10^-4 m2
I =1mA=1*10^-3A
N=500
theeta =60

so T =( 10^-3)*(10^-2)*(10^-3)*500*cos60
=250*10^-8 Nm
=2.5*10^-6 Nm

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