You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Physics

Magnetic Field Due to Current in a Solenoid

A coil of are...

Question

A coil of area $A$ , turns $N$ and carrying current $i$ is placed with its face parallel to the lines of magnetic induction $B$ . The work done in rotating the coil through an angle of $180^{0}$ is

i N A B

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 i N A B

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{i N A B}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Z e r o

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $2 i N A B$
The potential energy of a system of magnetic moment $\to M$ placed in magnetic field $\to B$ is $U = - \to M . \to B$
Hence the total work done in rotating the coil by $180^{\circ}$ is
$U_{2} - U_{1} = (M B) - (- M B)$
$= 2 M B = 2 i N A B$

Suggest Corrections

Similar questions

Q. When a current carrying coil is placed in a uniform magnetic field of induction

B

, then a torque

τ

acts on it. If

I

is the current,

n

is the number of turns and

A

is the face area of the coil and the normal to the coil makes an angle

θ

with

B

, Then

Q. A coil of area

100 c m^{2}

having

500

turns carries a current of

1 m A

. It is suspended in a uniform magnetic field of induction

10^{- 3} W b / m^{2}

. It's plane makes an angle of

60^{o}

with the lines of induction. The torque acting on the coil is :

A coil of area 100 cm^2 having 500 turns carries a current of 1 m A. It is suspended in a uniform magnetic field of induction 10^-3wb/m^2. Its plane making an angle of 60° with the lines of induction. the torque acting on the coil is

Q. The effective radius of a circular coil is

R

and the number of turns

N

. The current through it is

i

ampere. The work done is rotation the coil from angle

θ = 0^{o}

θ = 180^{o}

in an external magnetic field

B

will be.

Moving coil galvanometer operates on Permanent Magnet Moving Coll (PMMC) mechanism.

Moving coil galvanometers are of two types
(a) Suspended coll
(b) Pivoted coil type or tangent galvanometer,

Its working is based on the fact that when a current carrying coil is placed in a magnetic field, it experiences a torque. This torque tends to rotate the coil about its axis of suspension in such a way that the magnetic flux passing through the coil is maximum.

$(i v)$ In a moving coil galvanometer, having a coil of $N$ -turns of area $A$ and carrying current $I$ is placed in a radial field of strength $B$ . The torque acting on the coil is

Join BYJU'S Learning Program

A coil of area A, turns N and carrying current i is placed with its face parallel to the lines of magnetic induction B. The work done in rotating the coil through an angle of 1800 is

The correct option is A 2iNABThe potential energy of a system of magnetic moment →M placed in magnetic field →B is U=−→M.→BHence the total work done in rotating the coil by 180∘ isU2−U1=(MB)−(−MB)=2MB=2iNAB

A coil of area $A$ , turns $N$ and carrying current $i$ is placed with its face parallel to the lines of magnetic induction $B$ . The work done in rotating the coil through an angle of $180^{0}$ is

The correct option is A $2 i N A B$
The potential energy of a system of magnetic moment $\to M$ placed in magnetic field $\to B$ is $U = - \to M . \to B$
Hence the total work done in rotating the coil by $180^{\circ}$ is
$U_{2} - U_{1} = (M B) - (- M B)$
$= 2 M B = 2 i N A B$