Question

A coil of cross-sectional area $A$ having $n$ turns is placed in a uniform magnetic field $B$. When it is rotated with an angular velocity $\omega$, the maximum e.m.f. induced in the coil will be

• A. $nBA\omega$
• B. $\frac{3}{2}nBA\omega$
• C. $3nBA\omega$
• D. $\frac{1}{2}nBA\omega$

Answer 1

The correct option is A $nBA\omega$

Given, a coil of N turns an area A, rotated with angular speed $\omega$ in a uniform magnetic field B.

The flux linking to the coil, $\varphi =NBA$ sin$\left(\omega t\right)$

Therefore,

Induced EMF, $E=$d (NBA sin$\left(\omega t\right)\left)/dt\right)$

E= NBA $\omega$

Emax= NBA $\omega$