A coil of inductance 2H having negligible resistance is connected to a source of supply whose voltage is given by V=3tV, where t is time in s. If the voltage is applied when t=0, then the energy stored in the coil after 4s is _______J.
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Solution
We know that, V=Ldidt ⇒3t=Ldidt
⇒L∫i0di=3∫t0tdt
⇒Li=3t22
⇒i=3t22L=3×422×2=12A
Now, energy stored in the coil, E=12Li2=12×2×122=144J