A coil of inductance 8.4 mH and resistance 6Ω is connected to a 12 V battery. The current in the coil is 1.0 A at approximately the time
A
500 sec
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B
20 sec
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C
35 milli sec
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D
1 milli sec
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Solution
The correct option is D 1 milli sec Peak current in the circuits i0=126=2A Current decreases from 2A to 1A i.e., becomes half in time t=0.693LR=0.693×8.4×10−36=1 millisec.