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Question

A coil of inductance 8.4 mH and resistance 6 Ω is connected to a 12 V battery. The current in the coil is 1.0 A at approximately is
[Use ln2=0.693]

A
10 s
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B
10 ms
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C
1 s
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D
1 ms
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Solution

The correct option is D 1 ms

Given, L=8.4 mH ; R=6 ΩV=12 V ; I=1 A

The current growth in RL circuit is given by,

I=I01etτ

Where, I0=VR and τ=LR

I=VR1eRtL

1=126⎜ ⎜ ⎜1e6t(8.4×103)⎟ ⎟ ⎟

ln2=6t8.4×103

t=0.97×103 s=0.97 ms

t=1 ms

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (D) is the correct answer.

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