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Question

A coil of resistance 10Ω and an inductance 5 H are connected to a 100 volts battery. Then energy stored in the coil is :-

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Solution

Given:
R=10Ω
L=5H
V=100 volt
The energy stored in coil is given by , U=12Li2[i=VR]

U=12×5×(10010)2=250 J

Hence, option (d) is the correct answer.

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