wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A coil of resistance 300 Ω and inductance 1.0 H is connected across an alternating voltage of frequency 3002π Hz. Calculate the phase difference between the voltage and current in the circuit.

A
π4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
π3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
π
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
π6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A π4
Given: f=3002π Hz

ω=2πf=300 rad/s

Using phasor analysis,


XL=ωL=300×1=300 Ω

So, tanθ=XLR=300300=1

θ=45

So, phase difference between current and voltage in circuit =θ=45=π4

Hence, option (C) is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Alternating Current Applied to a Resistor
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon