A coil of resistance 400 - is placed in a magnetic field- If the magnetic flux - Wb linked with the coil varies with time ts as -50 t2-4- then current at 2 s is-A- 0-1 AB- 2 AC- 1 AD- 0-5 A

The correct option is D 0.5 Aϕ = 50t^2+4 emf=dϕ/dt=100t emf (t=2s)=100× 2=200V I=E/R=200/400=0.5A ...

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Standard XII

Physics

Magnetic Field Due to a Straight Long Wire

A coil of res...

Question

A coil of resistance $400 Ω$ is placed in a magnetic field. If the magnetic flux $ϕ$ (Wb) linked with the coil varies with time t(s) as $ϕ = 50 t^{2} + 4$ , then current at 2s is:

0.5 A

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0.1 A

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2 A

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1 A

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Solution

The correct option is A 0.5 A
$ϕ = 50 t^{2} + 4 e m f = \frac{d ϕ}{d t} = 100 t e m f (t = 2 s) = 100 \times 2 = 200 V I = \frac{E}{R} = \frac{200}{400} = 0.5 A$

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A coil of resistance 400Ω is placed in a magnetic field. If the magnetic flux ϕ (Wb) linked with the coil varies with time t(s) as ϕ=50t2+4, then current at 2s is:

The correct option is A 0.5 Aϕ=50t2+4emf=dϕdt=100temf(t=2s)=100×2=200VI=ER=200400=0.5A

A coil of resistance $400 Ω$ is placed in a magnetic field. If the magnetic flux $ϕ$ (Wb) linked with the coil varies with time t(s) as $ϕ = 50 t^{2} + 4$ , then current at 2s is:

The correct option is A 0.5 A
$ϕ = 50 t^{2} + 4 e m f = \frac{d ϕ}{d t} = 100 t e m f (t = 2 s) = 100 \times 2 = 200 V I = \frac{E}{R} = \frac{200}{400} = 0.5 A$