A coil of resistance 400 - is placed in a magnetic field- If the magnetic flux - W b linked with the coil varies with time t s as -50 t 2-4 - The induced current in the coil at t -2 s isA- 0-5 AB- 0-1 AC- 2 AD- 1 A

The correct option is A 0.5 AEmf generated israte of change of flux. So ε = dϕ/dt = d/dt (50t^2 + 4) = 100t V When, t = 2 s, |ε| = 200 V Induced curre ...

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Standard XII

Physics

Transformer

A coil of res...

Question

A coil of resistance $400$ $Ω$ is placed in a magnetic field. If the magnetic flux $ϕ (W b)$ linked with the coil varies with time $t (s)$ as $ϕ = 50 t^{2} + 4.$ The induced current in the coil at $t = 2 s$ is

0.5 A

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0.1 A

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2 A

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1 A

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Solution

The correct option is A $0.5 A$
Emf generated israte of change of flux.
So
$ε = - \frac{d ϕ}{d t} = - \frac{d}{d t} (50 t^{2} + 4) = - 100 t V$

When, $t = 2 s, | ε | = 200 V$
Induced current at $t = 2 s$ ,
$I = \frac{| ε |}{R} = \frac{200}{400} = 0.5 A$

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A coil of resistance 400 Ω is placed in a magnetic field. If the magnetic flux ϕ (Wb) linked with the coil varies with time t(s) as ϕ=50t2+4. The induced current in the coil at t=2 s is

The correct option is A 0.5 AEmf generated israte of change of flux. So ε=−dϕdt=−ddt(50t2+4)=−100t V When, t=2 s, |ε|=200 V Induced current at t=2 s, I=|ε|R=200400=0.5 A

A coil of resistance $400$ $Ω$ is placed in a magnetic field. If the magnetic flux $ϕ (W b)$ linked with the coil varies with time $t (s)$ as $ϕ = 50 t^{2} + 4.$ The induced current in the coil at $t = 2 s$ is

The correct option is A $0.5 A$
Emf generated israte of change of flux.
So
$ε = - \frac{d ϕ}{d t} = - \frac{d}{d t} (50 t^{2} + 4) = - 100 t V$

When, $t = 2 s, | ε | = 200 V$
Induced current at $t = 2 s$ ,
$I = \frac{| ε |}{R} = \frac{200}{400} = 0.5 A$