A coil of resistance 5Ω and inductance 4H is connected to a 10V battery. The energy stored in the coil
A
0.8J
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B
8J
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C
16J
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D
4J
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Solution
The correct option is B8J Initially, the inductor will oppose the flow of current but eventually the current in the circuit will be i=VR where V is voltage of the battery and R is the resistance. Energy stored in the inductor L : U=12Li2=12×4×(105)2=8J