CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A coil of wire has an area of 2.0x10-4 m2, consists of 100 loops or turns, and contains a current of 0.045 A. The coil is placed in a uniform magnetic field of magnitude 0.15 T. Determine the magnetic moment of the coil.


A

9.0 x 10-2 Am2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

9.0 x 10-3 Am2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

9.0 x 10-4 Am2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

9.0 x 10-5 Am2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is (D) 9.0 x 10-4 Am2



Given:

Area, A = 2.0x10-4 m2

Number of turns N = 100

Current I = 0.045 A

Magnetic field strength B = 0.15 T

We know,

Magnetic moment = N×I×A

Putting all the values

Magnetic moment = 100×0.045A×2×104=9×104 Am2

Hence the correct option is (D)


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Torque on a Magnetic Dipole
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon