Question

A coil of wire of resistance 50$\Omega$ is embedded in a block of ice. If a potential difference of 210 V is applied across the coil, the amount of ice melted per second will be

• A. 4.12 gm
• B. 4.12 kg
• C. 3.68 kg
• D. 2. 625 gm

Answer 1

The correct option is A 4.12 gm

$\text{Enthalpy of fusion" is the energy it takes to change from a solid to a liquid state}$

melt ice at 0 C to water at 0 C for water is 333.55 J/g per second.

Heat provided by resistor$=\frac{V^2}{R}=(210{)}^2/50$

Ice melted per second$=\frac{V^2}{R}=(210{)}^2/50\times \frac{1}{333.55}=2.6gram$