Question

A coin is kept at the bottom of an empty beaker. Water having refractive index $\frac{4}{3}$is poured into the beaker up to a height of 16 cm. Find the apparent position of the coin.

• A. 10 cm
• B. 12 cm
• C. 7.5 cm
• D. 2.5 cm

Answer 1

The correct option is B

12 cm

Given: Refractive index of water = $\frac{3}{4}$
$\text{Refractive Index}=\frac{\text{Real depth}}{\text{Apparent depth}}$
or, $\text{Apparent depth}=\frac{\text{Real depth}}{\text{Refractive Index}}$
or, $\text{Apparent depth}=\frac{16cm}{\frac{4}{3}}=12\text{cm}$