Question

A coin is placed 10 cm in front of a concave mirror. The mirror produces a real image that has diameter 4 times that of the coin. What is the image distance?

Answer 1

Given:

The object distance: $u=-10cm$

Magnification: $m=-4$ (-ve since the image is real)

We know that,

$m=\frac{-v}{u}=-4$

$⟹v=-40cm$

Hence, the image distance is $40cm$ in front of the mirror.