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Expression for Apparent Depth

A coin is pla...

Question

A coin is placed in a tumbler, water is then filled in the tumbler to a height of 20 cm. If the refractive index of water is 4/3, calculate the apparent depth of the coin. [2 MARKS]

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Solution

Problem: 2 Marks

Given:
Real depth $= h = 20 c m$

Refractive index $= n = \frac{4}{3}$

We know,
$n = \frac{R e a l d e p t h}{A p p a r e n t d e p t h}$

$\frac{4}{3} = \frac{20}{A p p a r e n t d e p t h}$

Therefore, Apparent depth $= 15 c m$

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