A coin is placed on a rotating turning table slips if it is placed at a minimum distance of $9 c m$ from the centre. If the angular velocity of the turn table is tripled, it will just slip if the distance from the centre is:

9 c m

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3 c m

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1.5 c m

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1 c m

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Solution

The correct option is D $1 c m$
$\frac{ω_{1}^{2}}{ω_{2}^{2}} = \frac{r_{2}}{r_{1}}$
$ω_{2} = 3 ω_{1}$ and $r_{1} = 9 c m$
$∴ \frac{ω_{1}^{2}}{9 ω_{1}^{2}} = \frac{r_{2}}{9} \Rightarrow r_{2} = 1 c m$

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A coin is placed on a rotating turning table slips if it is placed at a minimum distance of 9 cm from the centre. If the angular velocity of the turn table is tripled, it will just slip if the distance from the centre is:

The correct option is D 1 cmω21ω22=r2r1ω2=3ω1 and r1=9cm∴ω219ω21=r29⇒r2=1cm

A coin is placed on a rotating turning table slips if it is placed at a minimum distance of $9 c m$ from the centre. If the angular velocity of the turn table is tripled, it will just slip if the distance from the centre is:

The correct option is D $1 c m$
$\frac{ω_{1}^{2}}{ω_{2}^{2}} = \frac{r_{2}}{r_{1}}$
$ω_{2} = 3 ω_{1}$ and $r_{1} = 9 c m$
$∴ \frac{ω_{1}^{2}}{9 ω_{1}^{2}} = \frac{r_{2}}{9} \Rightarrow r_{2} = 1 c m$