A coin is thrown vertically upward with a velocity of 5 m/s. If the acceleration of the coin during its motion is 10 m/s2 in the downward direction, what will be the maximum height attained by the coin and how much time will it take to reach there?
S = 1.25 m, t = 0.5 s
Here,
u=5 m/s,a=−10 m/s2
At the highest point, v=0
Using v2=u2+2as,
0=52+[2×(−10)×s]
⇒s=1.25 m
Hence the height attained by the coin is 1.25 m.
Let time taken be t.
v=u+at
0=5−10t
t=0.5 s
Time taken by the coin to reach there is 0.5 s.