A coin is tossed $100$ times and head is obtained $59$ times. On tossing a coin at random, the probability of getting a tail is ______.

\frac{59}{100}

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1

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\frac{41}{100}

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Solution

The correct option is D $\frac{41}{100}$
$n (H e a d s) = 59$

Total tosses= $100$

Thus, $n (T a i l s) = 100 - 59 = 41$

Thus, $P (T a i l s) = \frac{41}{100}$

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Similar questions

Q. A coin is tossed 100 times and head is obtained 59 times. The probability of getting a tail is

(a)

\frac{59}{100}

(b)

\frac{41}{100}

(c)

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(d)

\frac{43}{100}

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A coin is tossed 100 times and head is obtained 59 times. On tossing a coin at random, the probability of getting a tail is ______.

The correct option is D 41100n(Heads)=59Total tosses=100Thus, n(Tails)=100−59=41Thus, P(Tails)=41100

A coin is tossed $100$ times and head is obtained $59$ times. On tossing a coin at random, the probability of getting a tail is ______.

The correct option is D $\frac{41}{100}$
$n (H e a d s) = 59$

Total tosses= $100$

Thus, $n (T a i l s) = 100 - 59 = 41$

Thus, $P (T a i l s) = \frac{41}{100}$