A coin is tossed $100$ times and tail is obtained $10$ times. Now, if a coin is tossed at random, what is the probability of getting a head?

\frac{11}{10}

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\frac{9}{10}

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\frac{90}{10}

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\frac{100}{10}

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Solution

The correct option is A $\frac{9}{10}$
Total number of trials $= 100$ .
Number of times tail appeared $= 10$ .
Number of times head appeared $= (100 - 10) = 90$

$P$ (Getting head) $=$ $\frac{N u m b e r o f t i m e s h e a d a p p e a r e d}{T o t a l n u m b e r o f t r i a l s}$

$=$ $\frac{90}{100}$ $=$ $\frac{9}{10}$

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A coin is tossed 100 times and tail is obtained 10 times. Now, if a coin is tossed at random, what is the probability of getting a head?

The correct option is A 910Total number of trials =100.Number of times tail appeared =10.Number of times head appeared =(100−10)=90P (Getting head) = Number of times head appearedTotal number of trials= 90100 = 910

A coin is tossed $100$ times and tail is obtained $10$ times. Now, if a coin is tossed at random, what is the probability of getting a head?