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Question

A coin is tossed '2n' times. The chance that the number of times one gets head is not equal to the number of times one gets tail is

A
(2n!)(n!)2.(12)2n
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B
1(2n!)(n!)2
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C
1(2n!)(n!)2.14n
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D
(2n!)(n!)214n
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Solution

The correct option is C 1(2n!)(n!)2.14n
Probability that the number of heads is equal to the number of tails (i.e. each occurs n times) = (2nnC)(2n)×(2n)=(2n)!(n!)2×14n
Therefore, the required probability = 1(2n)!(n!)2.14n

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