Question

A coin is tossed $3$ times then find probability of getting atleast two heads

• A. $\frac{1}{8}$
• B. $\frac{2}{8}$
• C. $\frac{3}{8}$
• D. $\frac{4}{8}$

Answer 1

Answer: (D)

$\frac{4}{8}$

A coin is tossed 3 times.

$S=TTT,TTH,THT,THH,HTT,HTH,HHT,HHH$,M=8

Here H denotes Head, T denotes Tail

There are N=4 elements in sample space having 2 heads

$P\left(E\right)=\frac{N}{M}=\frac{4}{8}$