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Question

A coin is tossed 5 times. Find the probability of getting at least 4 heads


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Solution

Finding the probability of getting at least 4 heads:

Number of times coin tossed, n =5

Number of possibilities =2 (H, T)

Number of possible outcomes n(S)=2n=25=32

P(All heads) =125=132

P(at least 4 heads)=px=4+p(x=5)

P(atleast4heads)=px=4+p(x=5)=C45121124+C55120125=5!4!5-4!121124+5!5!5-5!120125=5!4!1!121124+5!5!0!120125=5!4!121124+5!5!120125=5×4×3×2×14×3×2×112124+5×4×3×2×15×4×3×2×1125=5×12×116+132=532+132=632=316

Hence, the probability of getting at least 4 heads is 316.


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