Question

A coin is tossed $6$ times, find the probability of getting no tails.

• A. $\frac{1}{64}$
• B. $\frac{5}{64}$
• C. $\frac{1}{32}$
• D. $0.25$

Answer 1

The correct option is A $\frac{1}{64}$

Given: A coin tossed 6 times.

To find: the probability of getting no tails

Sol: Using Binomial Theorem ${}^n{C}_r\left(p{)}^r\right(q{)}^{n-r}$

Probability of getting a tail is $p=\frac{1}{2}$

And, the probability of NOT getting a tail is $q=\frac{1}{2}$

Here $n=6,r=0$

${}^6{C}_0\times {\left(\frac{1}{2}\right)}^0\times {\left(\frac{1}{2}\right)}^6=1\times$ $2^{-6}=\frac{1}{64}$

is the required probability of getting no tails.