A coin is tossed $75$ times and head comes $25$ times. Find the probability when a coin is tossed that a head will come.

\frac{1}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{2}{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $\frac{1}{3}$
$n (S) = 75$

$n (E) = 25$

$P (A) = \frac{N u m b e r o f f a v o r a b l e o u t c o m e s}{T o t a l N u m b e r o f p o s s i b l e o u t c o m e s}$

$P (A) = \frac{25}{75} = \frac{1}{3} .$

Suggest Corrections

Similar questions

Q. If a coin be tossed

n

times then the probability that the head comes odd times is

Q. A coin tossed

100

times. The no. of times head comes up is

54

.What is the probability of head coming up?

Q. There are three coins. One is a two-headed coin (having head on both faces), another is a biased coin that comes up heads

75

% of the times and third is also a biased coin that comes up tails

40

% of the times. One of the three coins is chosen at random and tossed, and it shows heads. What is the probability that it was the two-headed coin?

There are three coins. One is a two headed coin (having head on both faces), another is a biased coin that comes up heads 75% of the times and third is an unbiased coin. One of the three coins is chosen at random and tossed, it shows head, what is the probability that it is was the two headed coin?

Join BYJU'S Learning Program

A coin is tossed 75 times and head comes 25 times. Find the probability when a coin is tossed that a head will come.

The correct option is B 13n(S)=75 n(E)=25P(A)=Number of favorable outcomesTotal Number of possible outcomesP(A)=2575=13.

A coin is tossed $75$ times and head comes $25$ times. Find the probability when a coin is tossed that a head will come.

The correct option is B $\frac{1}{3}$
$n (S) = 75$

$n (E) = 25$

$P (A) = \frac{N u m b e r o f f a v o r a b l e o u t c o m e s}{T o t a l N u m b e r o f p o s s i b l e o u t c o m e s}$

$P (A) = \frac{25}{75} = \frac{1}{3} .$