Question

A coin is tossed A times and it showed tail B times. Find the probability of getting one head

Answer 1

$$\begin{gathered} Giventhat;Coinistossed\text{'}A\text{'}times\therefore TotalOutcomes=\mathit{A} \\ Itshowstail\text{'}\mathit{B}\text{'}timesoutof\text{'}\mathit{A}\text{'}times\therefore No.oftimesitshowsHEAD=\mathbf{(}\mathit{A}\mathbf{-}\mathit{B}\mathbf{)}\mathbf{}\mathbf{}\mathbf{}\mathbf{}(Favourableoutcomes) \\ Thus,P(gettingahead)=\frac{FavourableOutcomes}{TotalOutcomes} \\ =\frac{A-B}{A}=\mathit{1}\mathit{}\mathit{-}\mathit{}\frac{\mathit{B}}{\mathit{A}} \end{gathered}$$