A coin is tossed again and again. If tail appears on first three tosses, then the chance that head appears on fourth toss is

\frac{1}{16}

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\frac{1}{2}

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\frac{1}{8}

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\frac{1}{4}

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Solution

The correct option is A $\frac{1}{2}$
Since, events are independent, then probability of getting head in $4^{t h}$ toss $= \frac{1}{2}$

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Similar questions

A :

B :

C :

^{'} 6^{'}

D :

^{'} 1^{'}

A fair coin is tossed a number of times. If head appears on all the 4 tosses, what is the probability that a tail appears on the 5^th toss?

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