Question

A coin is tossed four times, If $H$ = head and $T$ = tail, what is the probability of the tosses coming up in the order $HTHH$.

• A. $3/16$
• B. $1/16$
• C. $5/16$
• D. $7/16$

Answer 1

The correct option is B $1/16$

Probability of head H=1/2 and of tail T=1/2

Probability of HTHH=${\left(\frac{1}{2}\right)}^4=\frac{1}{16}$