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Question

A coin is tossed repeatedly until it shows head. Let X be the number of tosses required to get head. Write the probability distribution of X.

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Solution

Suppose the head appears in xth toss. This means that tail appears in all preceding (x1) tosses.
Now, if p is the probability of getting a head then probability of getting a tail is 1p=q. So, the probability function of x will be f(x)=qx1p for x=1,2,3….. Now the expected of tosses will be
E(x)=εx=1xqx1p=pqεx=1xqx=pqq(1+2q+3q2+....)
=pqq(1q)2=1pq.

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