Question

A coin is tossed three times. Find the probability that heads and tails will appear alternatively. Give the answer up to 2 decimal places

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Answer 1

All possible outcomes are: HHH, HHT, HTH, HTT, TTT, TTH, THT, THH.
There are two favourable outcomes for this event: THT, HTH.

We know that, Probability of an event E, P(E) =$\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}$
Since there are total of 8 possible outcomes, the probability of the given event happening is $\frac{2}{8}$, which is, 0.25