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Question

# A coin is tossed twice. Find the probability of getting: (i) exactly one head (ii) exactly one tail (iii) two tails (iv) two heads

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Solution

## When a coins tossed twice, the all possible results are HH, HT, TH, TT.Total number of possible out comes =4Probability of an event =Number of favourable outcomesTotal number of possible outcomes(i) Exactly one head,Number of possible out comes =2 ( HT, TH).Probability of an event getting exactly one head=24=12(ii) Exactly one tail,Number of possible out comes =2 ( HT, TH).Probability of an event getting exactly one tail=24=12(iii) Two tails,Number of possible out comes =1 ( TT).Probability of an event getting exactly one head=14(iii) Two heads,Number of possible out comes =1 (HH).Probability of an event getting exactly one head=14 ∴ \therefore=24=12 =\frac{2}{4} = \frac{1}{2

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