Question

A coin is tossed twice. What is the probability of getting two consecutive heads ?

• A. $\frac{1}{4}$
• B. $\frac{1}{2}$
• C. $1$
• D. $0$

Answer 1

The correct option is A $\frac{1}{4}$

There are 4 possibilities I.e the sample space is

$HH,HT,TH,TT$

Atleast one head occurs in three of the above mentioned possibilities.

Here S is the sample space

And N is the number of items in a set

$N\left(2H\right)=1$

$N\left(S\right)=4$

Thus$P=N\left(2H\right)/N\left(S\right)=\frac{1}{4}$