A coin is tossed twice what is the probability that at least one tail occurs?

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Solution

When a coin is tossed twice the sample space is given by
$S = {H H, H T, T H, T T}$
Let $A$ be the event of the occurrence of at least one tail
$\Rightarrow A = {H T, T H, T T}$
$∴ P (A) = \frac{n (A)}{n (S)} = \frac{3}{4}$

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A coin is tossed twice what is the probability that at least one tail occurs?

When a coin is tossed twice the sample space is given byS={HH,HT,TH,TT}Let A be the event of the occurrence of at least one tail⇒A={HT,TH,TT}∴P(A)=n(A)n(S)=34

When a coin is tossed twice the sample space is given by
$S = {H H, H T, T H, T T}$
Let $A$ be the event of the occurrence of at least one tail
$\Rightarrow A = {H T, T H, T T}$
$∴ P (A) = \frac{n (A)}{n (S)} = \frac{3}{4}$