Question

A coin is tossed two times. Find the probability of getting at most one head.

• A. 0.75
• B. 0.65
• C. 0.25
• D. 0.55

Answer 1

The correct option is A

0.75

The possible outcomes, if a coin is tossed 2 times is

S = {HH, HT, TH, TT}; n(S) = 4

Let E = Event of getting at most one head

E = {HT, TH, TT}; n(E) = 3

Hence, the required probability = $\frac{n\left(E\right)}{n\left(S\right)}$ = $\frac{3}{4}$ = 0.75