Question

A coin tossed three times. Find the chance that head and tail show alternately.

• A. $\frac{3}{8}$
• B. $\frac{1}{4}$
• C. $\frac{1}{8}$
• D. None of these

Answer 1

The correct option is B $\frac{1}{4}$

Sample space S = {HHH, HHT, HTH, HTT, TTH, THH, TTT}

Number of exhaustive cases = 8

Favourable case are HTH, THT

Number of favorable cases = 2

$\therefore Requiredprobability=\frac{2}{8}=\frac{1}{4}$