Question

A coin whose faces are marked by $3,4$ is tossed $5$ times the probability of getting a total of $24$ is

• A. $\frac{1}{12}$
• B. $\frac{5}{32}$
• C. $\frac{5}{16}$
• D. $0$

Answer 1

The correct option is D $0$

When we toss a coin whose face are marked 3 and 4 five time then sum
of the number appeared on the coin will lie in the range $[15,20]$
which means we never get the sum $24$
Hence requited probability is $0$.