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Work Energy Theorem

A collar of m...

Question

A collar of mass 10 kg is released from rest from position A, when spring is in natural length and slides along a rough vertical fixed rod. The block comes to rest at point B, 4 m below the point A. The spring constant of spring is 100 N/m and natural length of spring is 3 m. Find work done by friction (‘O’ is a fixed point)

A

-100 J

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B

-200 J

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C

-300 J

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D

-400 J

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Solution

The correct option is B
-200 J

The energy stored in the spring = $\frac{1}{2} k x_{0}^{2} = 200 J .$ Loss in energy due to gravity = mg(AB) = 400J.
Hence loss in energy due to friction = 200 – 400 = – 200 J

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