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Zinc Ion

A colorless s...

Question

A colorless solid (A), when placed into water, produces heavy white turbidity to (B). Solid (A) gives a clear solution in $c o n c . H C l$ when $H C l$ solution is added to large amounts of water, (B) forms again. (B) dissolves in dilute HCl. When $H_{2} S$ is passed through a suspension of (A) or (B); a black precipitate (C) forms, (C) is insoluble in yellow ammonium sulphide $(N H_{4})_{2} S$ . $C o n c . H_{2} S O_{4}$ added to solid (A) liberates gas (D). Gas(D) is water-soluble and gives white precipitate with mercuric salts (E) and not mercuric salts. The black precipitate (C) dissolves in $H N O_{3}$ (1:1) to give a solution to which $H_{2} S O_{4}$ is added followed by addition of $N H_{4} O H$ when a white precipitate (F) is formed. (E) gives a black ppt. (G) with a solution of sodium stannite.

Compound B is not soluble in:

A

tartaric acid

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B

H C l

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C

H N O_{3}

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D

H_{2} S O_{4}

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Solution

The correct option is A tartaric acid
$\begin{matrix} B i C l_{3} & + & H_{2} O & ⟶ & B i O C l ↓ & + & 2 H C l (A) & w h i t e p p t . (B) \end{matrix}$
$\begin{matrix} B i O C l & + & 2 H C l & ⟶ & B i C l_{3} & + & H_{2} O (B) & (A) \end{matrix}$
$\begin{matrix} 2 B i C l_{3} & + & 3 H_{2} S & ⟶ & B i_{2} S_{3} ↓ & + & 6 H C l b r o w n - b l a c k p p t . (C) \end{matrix}$
$B i_{2} S_{3} + 8 H N O_{3} ⟶ 2 B i (N O_{3})_{3} + 3 S ↓ + 2 N O + 4 H_{2} O$
$2 B i (N O_{3})_{3} + 3 H_{2} S O_{4} ⟶ B i_{2} (S O_{4})_{3} + 6 H N O_{3}$
$\begin{matrix} B i_{2} (S O_{4})_{3} & + & 6 N H_{4} O H & ⟶ & 2 B i (O H)_{3} ↓ & + & 3 (N H_{4})_{2} S O_{4} w h i t e p p t . (F) \end{matrix}$
$\begin{matrix} 2 B i (O H)_{3} & + & 3 N a_{2} S n O_{2} & ⟶ & 2 B i & + & 3 N a_{2} S n O_{3} & + & H_{2} O (G) b l a c k p p t . \end{matrix}$
$\begin{matrix} 2 B i C l_{3} & + & 3 H_{2} S O_{4} & ⟶ & B i_{2} (S O_{4})_{3} & + & 6 H C l (D) \end{matrix}$
$\begin{matrix} H g_{2} (N O_{3})_{2} & + & 2 H C l & ⟶ & H g_{2} C l_{2} ↓ & + & 2 H N O_{3} w h i t e p p t . (E) \end{matrix}$

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