Question

A colour blind male $\left(X^{c}Y\right)$ marries a carrier female $\left(X^C{X}^c\right)$. Possible genotype of daughters will be _______________.

• A. $X^c{X}^c$ only
• B. $X^C{X}^C$ only
• C. $X^C{X}^C$ and $X^c{X}^c$
• D. $X^C{X}^c$ and $X^c{X}^c$

Answer 1

The correct option is D $X^C{X}^c$ and $X^c{X}^c$

Color blindness is X-linked recessive. The daughter will get one X chromosome from her father and one X chromosome from her mother. Father will contribute the affected X chromosome whereas mother can the affected X chromosome or she can pass the normal X chromosome.

So, the correct answer is '$X^C{X}^c$ and $X^c{X}^c$'.