Question

A combination of logic gates has the truth table below.

$P$	$Q$	$Z$
$0$	$0$	$0$
$0$	$1$	$1$
$1$	$0$	$1$
$1$	$1$	$1$

Which of the following combinations has this truth table ?

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

(A) $Z=\overline{(\overline{P}+Q)}$

$P$	$Q$	$Z$
$0$	$0$	$0$
$0$	$1$	$0$
$1$	$0$	$1$
$1$	$1$	$0$

(B) $Z=\overline{(\overline{P}.Q)}$

$P$	$Q$	$Z$
$0$	$0$	$1$
$0$	$1$	$0$
$1$	$0$	$1$
$1$	$1$	$1$

(C) $Z=\overline{(\overline{Q}.\overline{(P+Q))})}$

$P$	$Q$	$Z$
$0$	$0$	$0$
$0$	$1$	$1$
$1$	$0$	$1$
$1$	$1$	$1$

(D) $Z=\overline{(P.Q)}$

$P$	$Q$	$Z$
$0$	$0$	$1$
$0$	$1$	$1$
$1$	$0$	$1$
$1$	$1$	$0$