CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A combination of secondary cells has an equivalent EMF of 2 V. Due to long use they have a large equivalent resistance of 400 Ω. What maximum current can be drawn?
  1. 0.005 A
  2. 0.0005 A
  3. 0.010 A
  4. None of these


Solution

The correct option is A 0.005 A
Ok. So what the question tells you is that the battery comes with a resistance of 400Ω of its own. Now we want to maximize the current we can draw from this resistor. That can only be a maximum if we connect the least possible resistance across it. That would be 0 Ω. Connecting 0 Ω across the terminals of the battery is called shorting the terminals of the battery. Now that means we have a circuit like this –

The current will simply be i=VR
i=2400=0.005A

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More


People also searched for
View More



footer-image