A combination of secondary cells has an equivalent EMF of 2 V. Due to long use they have a large equivalent resistance of 400 Ω. What maximum current can be drawn?
None of these
The correct option is A0.005 A Ok. So what the question tells you is that the battery comes with a resistance of 400Ω of its own. Now we want to maximize the current we can draw from this resistor. That can only be a maximum if we connect the least possible resistance across it. That would be 0 Ω. Connecting 0 Ω across the terminals of the battery is called shorting the terminals of the battery. Now that means we have a circuit like this –