A commercial cylinder contains 6-91m3 of O2 at 15M Pa and 21-C-the cricital constants for O2 are Tc- 126-C-Pc-50 bar-Determine the reduced pressure and reduced temperature for O2under these conditions-

The correct option is B P_R=3,T_R=2 The reduced pressure π = P/P_c = nbsp; nbsp; 150 atm/50 atm = 3 The reduced temperature θ = T/T_c = ...

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Byju's Answer

Standard XII

Chemistry

Liquefaction of Gases and Critical Constants

A commercial ...

Question

A commercial cylinder contains $6.91 m^{3}$ of $O_{2}$ at 15M Pa and $21^{\circ}$ C.the cricital constants for $O_{2}$ are $T_{c}$ =- $126^{\circ} C, P_{c} = 50$ bar.Determine the reduced pressure and reduced temperature for $O_{2}$ under these conditions:

P_{R} = 2, T_{R} = 3

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P_{R} = 3, T_{R} = 2

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P_{R} = 6, T_{R} = 4

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P_{R} = 4, T_{R} = 6

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Solution

The correct option is B $P_{R} = 3, T_{R} = 2$
The reduced pressure $π = \frac{P}{P_{c}} = \frac{150 a t m}{50 a t m} = 3$
The reduced temperature $θ = \frac{T}{T_{c}} = \frac{21 + 273}{273 - 126} = \frac{294}{147} = 2$

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Similar questions

Q. A commercial cylinder contains 6.01

m^{3}

O_{2}

at 15.18 M Pa and

21^{\circ} C

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T_{c} = - {118.4}^{\circ} C, P_{c} = 50.1

atm. Determine the reduced pressure and reduced temperature for

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under these conditions.

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\frac{P}{P_{c}} = P_{r}, \frac{T}{T_{c}} = T_{r}, a n d \frac{V_{m}}{V_{m, c}} = V_{r}

where

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P_{c}

is critical pressure

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is reduced temperature,

T_{c}

is critical temperature

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is reduced volume,

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is critical volume
then the equation of state (or van der Waals equation), only in terms of

P_{r}, T_{r}

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The volume occupied by 2 mol of $N_{2}$ at 200 K and 10.1325 MPa pressure is

(Given that $\frac{P_{c} V_{C}}{R T_{C}} = \frac{3}{8}$ and $\frac{P_{r} V_{r}}{T_{r}} = 2.21$ ), where $P_{r}, V_{r}$ and $T_{r}$ are reduced pressure, reduced volume and reduced temperature.

In Fig. T is a point on side QR of $Δ P Q R$ and S is a point such that RT = ST. Which of the following is true?

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A commercial cylinder contains 6.91m3 of O2 at 15M Pa and 21∘C.the cricital constants for O2 are Tc=-126∘C,Pc=50 bar.Determine the reduced pressure and reduced temperature for O2under these conditions:

The correct option is B PR=3,TR=2The reduced pressure π=PPc=150atm50atm=3The reduced temperature θ=TTc=21+273273−126=294147=2

A commercial cylinder contains $6.91 m^{3}$ of $O_{2}$ at 15M Pa and $21^{\circ}$ C.the cricital constants for $O_{2}$ are $T_{c}$ =- $126^{\circ} C, P_{c} = 50$ bar.Determine the reduced pressure and reduced temperature for $O_{2}$ under these conditions:

The correct option is B $P_{R} = 3, T_{R} = 2$
The reduced pressure $π = \frac{P}{P_{c}} = \frac{150 a t m}{50 a t m} = 3$
The reduced temperature $θ = \frac{T}{T_{c}} = \frac{21 + 273}{273 - 126} = \frac{294}{147} = 2$