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Question

A committee of 7 has to be formed from 9 boys and 4 girls. In how many ways can this be done when the committee consists of: (i) exactly 3 girls? (ii) atleast 3 girls? (iii) atmost 3 girls?

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Solution

It is given that a committee of 7 has to be formed from 9 boys and 4 girls.

(i)

Since exactly 3 girls have to be selected from 4 girls, thus it can be shown as the number of girls is the combination of 4 girls taken 3 at a time.

The formula for the combination is defined as,

C n r = n! ( nr )!r! .

Substitute 4 for n and 3 for r in the above formula.

C 4 3 = 4! ( 43 )!3! = 4! 1!3!

Cancel the common factors by factorizing the bigger term to the factorial.

The formula to calculate the factors of a factorial in terms of factorial itself is,

n!=n( n1 )! n!=n( n1 )( n2 )![ n2 ]

The combination can be written as,

C 4 3 = 4×3! 3!1! = 4 1 =4

Thus, the number of ways that the girls are selected is 4.

Since the committee consists of total 7 members from which 3 are girls then the number of boys will be, 73=4 .Therefore, 4 boys have to be selected from 9 boys, thus it can be shown as the number of boys is the combination of 9 boys taken 4 at a time.

The formula for the combination is defined as,

C n r = n! ( nr )!r! .

Substitute 9 for n and 4 for r in the above formula.

C 9 4 = 9! ( 94 )!4! = 9! 5!4!

Cancel the common factors by factorizing the bigger term to the factorial.

The formula to calculate the factors of a factorial in terms of factorial itself is,

n!=n( n1 )! n!=n( n1 )( n2 )![ n2 ]

The combination can be written as,

C 9 4 = 9×8×7×6×5! 5!4×3×2×1 = 9×8×7×6 4×3×2×1 =126

Thus, the number of ways that the boys are selected is 126.

By multiplication principle which states that if an event can occur in m different ways and follows another event that can occur in n different ways, the number of ways that exactly 3 girls are selected is 4×126=504 .

(ii)

If at least 3 girls are to be selected, then the condition arises that the girls can be more than 3 but not less than 3. In this case, two cases that arise are as follows:

(a) 3 girls and 4 boys.

(b) 4 girls and 3 boys.

In case (a), 3 girls are chosen from 4 girls, thus the combination can be written as C 4 3 .

The formula for the combination is defined as,

C n r = n! ( nr )!r! .

Substitute 4 for n and 3 for r in the above formula.

C 4 3 = 4! ( 43 )!3! = 4! 1!3!

Cancel the common factors by factorizing the bigger term to the factorial.

The formula to calculate the factors of a factorial in terms of factorial itself is,

n!=n( n1 )! n!=n( n1 )( n2 )![ n2 ]

The combination can be written as,

C 4 3 = 4×3! 3!1! = 4 1 =4

Thus, the number of ways that the girls are selected is 4.

Also 4 boys are chosen from 9 boys, thus the combination is C 9 4 .

The formula for the combination is defined as,

C n r = n! ( nr )!r! .

Substitute 9 for n and 4 for r in the above formula.

C 9 4 = 9! ( 94 )!4! = 9! 5!4!

Cancel the common factors by factorizing the bigger term to the factorial.

The formula to calculate the factors of a factorial in terms of factorial itself is,

n!=n( n1 )! n!=n( n1 )( n2 )![ n2 ]

The combination can be written as,

C 9 4 = 9×8×7×6×5! 5!4×3×2×1 = 9×8×7×6 4×3×2×1 =126

Thus, the number of ways that the boys are selected is 126.

By multiplication principle which states that if an event can occur in m different ways and follows another event that can occur in n different ways, the number of ways that exactly 3 girls and 4 boys are selected is 4×126=504 .

In case (b), 4 girls are chosen from 4 girls, thus the combination can be written as C 4 4 .

The formula for the combination is defined as,

C n r = n! ( nr )!r! .

Substitute 4 for n and 4 for r in the above formula.

C 4 4 = 4! ( 44 )!4! = 4! 0!4! = 1 1 =1

Thus, the number of ways that the girls are selected is 1.

Also 3 boys are chosen from 9 boys, thus the combination is C 9 3 .

The formula for the combination is defined as,

C n r = n! ( nr )!r! .

Substitute 9 for n and 3 for r in the above formula.

C 9 3 = 9! ( 93 )!3! = 9! 6!3!

Cancel the common factors by factorizing the bigger term to the factorial.

The formula to calculate the factors of a factorial in terms of factorial itself is,

n!=n( n1 )! n!=n( n1 )( n2 )![ n2 ]

The combination can be written as,

C 9 3 = 9×8×7×6! 6!3×2×1 = 9×8×7 3×2×1 =84

Thus, the number of ways that the boys are selected is 84.

By multiplication principle which states that if an event can occur in m different ways and follows another event that can occur in n different ways, the number of ways that exactly 4 girls and 3 boys are selected is 1×84=84 .

Thus, the number of ways that at least 3 girls are selected is 504+84=588 .

(iii)

If at most 3 girls are to be selected, then the condition arises that the girls can be less than 3 but not more than 3. In this case, following cases arises:

(a) 3 girls and 4 boys.

(b) 2 girls and 5 boys.

(c) 1 girl and 6 boys.

(d) No girl and 7 boys.

In case (a), 3 girls are chosen from 4 girls, thus the combination can be written as C 4 3 .

The formula for the combination is defined as,

C n r = n! ( nr )!r! .

Substitute 4 for n and 3 for r in the above formula.

C 4 3 = 4! ( 43 )!3! = 4! 1!3!

Cancel the common factors by factorizing the bigger term to the factorial.

The formula to calculate the factors of a factorial in terms of factorial itself is,

n!=n( n1 )! n!=n( n1 )( n2 )![ n2 ]

The combination can be written as,

C 4 3 = 4×3! 3!1! = 4 1 =4

Thus, the number of ways that the girls are selected is 4.

Also 4 boys are chosen from 9 boys, thus the combination is C 9 4 .

The formula for the combination is defined as,

C n r = n! ( nr )!r!

Substitute 9 for n and 4 for r in the above formula.

C 9 4 = 9! ( 94 )!4! = 9! 5!4!

Cancel the common factors by factorizing the bigger term to the factorial.

The formula to calculate the factors of a factorial in terms of factorial itself is,

n!=n( n1 )! n!=n( n1 )( n2 )![ n2 ]

The combination can be written as,

C 9 4 = 9×8×7×6×5! 5!4×3×2×1 = 9×8×7×6 4×3×2×1 =126

Thus, the number of ways that the boys are selected is 126.

By multiplication principle which states that if an event can occur in m different ways and follows another event that can occur in n different ways, the number of ways that 3 girls and 4 boys are selected is 4×126=504 .

In case (b), 2 girls are chosen from 4 girls, thus the combination can be written as C 4 2 .

The formula for the combination is defined as,

C n r = n! ( nr )!r! .

Substitute 4 for n and 2 for r in the above formula.

C 4 2 = 4! ( 42 )!2! = 4! 2!2! = 4×3×2! 2!2×1 =6

Thus, the number of ways that the girls are selected is 6.

Also 5 boys are chosen from 9 boys, thus the combination is C 9 5 .

The formula for the combination is defined as,

C n r = n! ( nr )!r! .

Substitute 9 for n and 5 for r in the above formula.

C 9 5 = 9! ( 95 )!5! = 9! 4!5! = 9×8×7×6×5! 5!4×3×2×1 =126

Thus, the number of ways that the boys are selected is 126.

By multiplication principle which states that if an event can occur in m different ways and follows another event that can occur in n different ways, the number of ways that 2 girls and 5 boys are selected is 6×126=756 .

In case (c), 1 girl is chosen from 4 girls, thus the combination can be written as C 4 1 .

The formula for the combination is defined as,

C n r = n! ( nr )!r! .

Substitute 4 for n and 1 for r in the above formula.

C 4 1 = 4! ( 41 )!1! = 4! 3!1! = 4×3! 3!1 =4

Thus, the number of ways that the girls are selected is 4.

Also 6 boys are chosen from 9 boys, thus the combination is C 9 6 .

The formula for the combination is defined as,

C n r = n! ( nr )!r! .

Substitute 9 for n and 6 for r in the above formula.

C 9 6 = 9! ( 96 )!6! = 9! 3!6! = 9×8×7×6! 6!3×2×1 =84

Thus, the number of ways that the boys are selected is 84.

By multiplication principle which states that if an event can occur in m different ways and follows another event that can occur in n different ways, the number of ways that 1 girl and 6 boys are selected is 4×84=336 .

In case (d), no girl is chosen from 4 girls, thus the combination can be written as C 4 0 .

The formula for the combination is defined as,

C n r = n! ( nr )!r! .

Substitute 4 for n and 0 for r in the above formula.

C 4 0 = 4! ( 40 )!0! = 4! 4!0! = 1 1 =1

Thus, the number of ways that the girls are selected is 1.

Also 7 boys are chosen from 9 boys, thus the combination is C 9 7 .

The formula for the combination is defined as,

C n r = n! ( nr )!r! .

Substitute 9 for n and 7 for r in the above formula.

C 9 7 = 9! ( 97 )!7! = 9! 2!7! = 9×8×7! 7!2×1 =36

Thus, the number of ways that the boys are selected is 36.

By multiplication principle which states that if an event can occur in m different ways and follows another event that can occur in n different ways, the number of ways that no girl and 7 boys are selected is 1×36=36 .

Thus, the number of ways that at most 3 girls are selected is, 504+756+336+36=1632


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