A common base transistor amplifier has a current gain of 50. If the load resistance is 4kΩ, and input resistance is 500Ω, the voltage gain of amplifier is
A
100
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B
200
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C
300
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D
400
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Solution
The correct option is D400 Given that: β=50 RL=4kΩ=4000Ω Ri=500Ω Hence, resistance gain is RLRi=4000500=8
For CB amplifier, voltage gain is, Voltage gain = Current gain × Resistance gain Voltage gain = 50×8 Voltage gain = 400.