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P-N Junction

A common base...

Question

A common base transistor amplifier has a current gain of $50$ . If the load resistance is $4 k Ω$ , and input resistance is $500 Ω$ , the voltage gain of amplifier is

A

100

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B

200

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C

300

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D

400

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Solution

The correct option is B $400$
Given that: $β$ $= 50$
$R_{L} = 4 k Ω = 4000 Ω$
$R_{i} = 500 Ω$
Hence, Resistance gain is, $\frac{R_{L}}{R_{i}} = \frac{4000}{500} = 8$

For CB amplifier voltage gain is:
Voltage gain $=$ Current gain $\times$ Resistance gain
Voltage gain $= 50 \times 8$
Voltage gain $= 400$

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