A common emitter amplifier is designed with n-p-n transistor -0-99- The input impedance is 1 K - and the load is 10 K - The voltage gain will be-A- 99B- 9-9C- 990D- 9900

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A common emit...

Question

A common emitter amplifier is designed with n-p-n transistor (α =0.99). The input impedance is 1 KΩ and the load is 10 KΩ. The voltage gain will be.

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9900

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990

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9.9

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(α = 0.99)

1

Ω

10

Ω

β = 100

R_{1} = 1 k Ω

R_{2} = 10 k Ω

α =

0.99

0.45 M Ω

50 Ω

60 d B

100 Ω

10 k Ω

β

800

α =

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