Question

A common emitter transistor amplifier has a current gain of $50$. If the load resistance is $4k$$\Omega$, and input resistance is $500\Omega$, the voltage gain of amplifier is :

• A. $100$
• B. $200$
• C. $300$
• D. $400$

Answer 1

The correct option is D $400$

Given:

$\beta =50$

$R_L=4k\Omega$

$R_i=500\Omega$

The resistance gain is given by,

$\frac{R_L}{R_i}=\frac{4000}{500}=8$

Now, the voltage gain is

$A_v=\beta \left(\frac{R_L}{R_i}\right)$

$A_v=\left(50\right)\left(8\right)=400$