Question

A common-emitter transistor amplifier has a current gain of $50$. If the load resistance is $4k\Omega$ and input resistance is $500\Omega$, then the voltage gain of the amplifier is:

• A. $160$
• B. $200$
• C. $300$
• D. $400$

Answer 1

The correct option is D $400$

In common-emitter transistor amplifier,

$\beta =50$

$R_i=500\Omega$

$R_0=4k\Omega$

$\beta =\frac{I_c}{I_B}=50$

Voltage gain of the amplifier,

$A_v=\frac{V_0}{V_i}$

$A_v=\frac{V_{CE}}{V_{BE}}=\frac{I_C{R}_0}{I_B{R}_i}$

$A_v=\frac{50\times 4\times 1000}{500}=400$

The correct option is D.